1.What is the formula to calculate compound interest (CI) after n years at r% rate with principal P?
A. CI = P × r × n
B. CI = P × (1 + r100)ⁿ
C. CI = P × [(1 + r100)ⁿ – 1]
D. CI = P + (r × n)
Answer: C. CI = P × [(1 + r100)ⁿ – 1]
2.If ₹10,000 is compounded annually at 5% for 3 years, what will be the amount?
A. ₹11,500
B. ₹11,576.25
C. ₹11,650
D. ₹11,000
Answer: B. ₹11,576.25
3.A value decreases at 10% per year for 2 years. If the initial value is ₹20,000, the value after 2 years is:
A. ₹18,000
B. ₹17,000
C. ₹16,200
D. ₹15,000
Answer: C. ₹16,200
4.What happens when the compounding frequency increases?
A. Interest decreases
B. Interest remains same
C. Interest becomes zero
D. Interest increases
Answer: D. Interest increases
5.If a population grows uniformly at 4% annually, and the current population is 5,000, what will it be after 3 years (approx.)?
A. 5,400
B. 5,500
C. 5,624
D. 6,000
Answer: C. 5,624