Compound Interest and Uniform Rate of Increase or Decrease

Compound Interest and Uniform Rate of Increase or Decrease

Compound Interest and Uniform Rate of Increase or Decrease

Multiple Choice Questions (MCQ)

1.What is the formula to calculate compound interest (CI) after n years at r% rate with principal P?

A. CI = P × r × n
B. CI = P × (1 + r100)ⁿ
C. CI = P × [(1 + r100)ⁿ – 1]
D. CI = P + (r × n)

 Answer: C. CI = P × [(1 + r100)ⁿ – 1]

2.If ₹10,000 is compounded annually at 5% for 3 years, what will be the amount?

A. ₹11,500
B. ₹11,576.25
C. ₹11,650
D. ₹11,000

Answer: B. ₹11,576.25

3.A value decreases at 10% per year for 2 years. If the initial value is ₹20,000, the value after 2 years is:

A. ₹18,000
B. ₹17,000
C. ₹16,200
D. ₹15,000

 Answer: C. ₹16,200

4.What happens when the compounding frequency increases?

A. Interest decreases
B. Interest remains same
C. Interest becomes zero
D. Interest increases

Answer: D. Interest increases

5.If a population grows uniformly at 4% annually, and the current population is 5,000, what will it be after 3 years (approx.)?

A. 5,400
B. 5,500
C. 5,624
D. 6,000

 Answer: C. 5,624

Short Answer Questions (SAQ)

1. Write the formula to find the final amount when interest is compounded semi-annually.

Answer: A=P(1+r2100)2n

2. State one difference between compound interest and simple interest.

 Answer: Compound interest is calculated on both principal and accumulated interest, while simple interest is calculated only on the principal.

3. If a quantity increases by 5% each year, what is the multiplier used in the formula?

 Answer: The multiplier is (1+5100) = 1.05 

Long Answer Questions (LAQ)

1. A sum of ₹12,000 is compounded annually at 6% for 2 years. Find the amount and compound interest.

 Answer: Given: P = ₹12,000, r = 6%, n = 2
Amount:
A = 12000 × (1+6100)2 = 12000 × (1.06)2 = 12000 × 1.1236 = ₹13,483.20
Compound Interest:
CI = A − P = 13,483.20 − 12,000 = ₹1,483.20

2. A car costs ₹5,00,000 and depreciates by 12% annually. What will be its value after 2 years?

 Answer: Given: Original value = ₹5,00,000, r = 12%, n = 2
New Value:
= 500000 × (1−12100)2 = 500000 × (0.88)2 = 500000 × 0.7744 = ₹3,87,200

 Answer: The car’s value after 2 years will be ₹3,87,200.

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